my js ROUND3
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my js ROUND3
30. Jun 2011 00:55:36 (12y 305d)
30. Jun 2011 00:55:36 (12y 305d)
The goal of this round is to make a script that outputs:
'the quick brown fox jumps over the lazy dog'
rule1: you may only use 3 or less words from the sentence in your code(this includes encoding the words in any form e.g. base64, hex, etc etc)
rule2: standalone script, no external source/s
Good luck and Happy coding ;)
'the quick brown fox jumps over the lazy dog'
rule1: you may only use 3 or less words from the sentence in your code(this includes encoding the words in any form e.g. base64, hex, etc etc)
rule2: standalone script, no external source/s
Good luck and Happy coding ;)
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RE: my js ROUND3
1. Jul 2011 02:56:57 (12y 304d)
1. Jul 2011 02:56:57 (12y 304d)
my first try, 324
GeSHi`ed javascript Quelltext
1 | x='';s=x+((((((2577*450)+8)*9*369)+1)*2)*11)+(((((4027*90)+1)*23)*74)*93)+((((226*1450)+7)*307)*823)+'0'+(((((20*1280)*1724)+6)*181)-1)+((((32*1031)*1340)*1760)-2)+((((((9007*40)-5)*1162)+3)*160)-8)+(((92830*1118)-9)*668)+((581114*1605)+1);for(i=0;i<=85;i++){x=x+String.fromCharCode(s.substr(i,2)).toLowerCase();i++}alert(x) |
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RE: my js ROUND3
1. Jul 2011 03:13:05 (12y 304d)
1. Jul 2011 03:13:05 (12y 304d)
My first try
Just as a reference, 4 bytes per char + 5.
Happy Challenging!
PS: Is there a site for javascript codegolf yet?
GeSHi`ed javascript Quelltext für 177
1 2 3 | $x="\x74\x68\x65\x20\x71\x75\x69\x63\x6b\x20\x62\x72\x6f\x77\x6e\x20\x66\x6f\x78\x20\x6a\x75\x6d\x70\x73\x20\x6f\x76\x65\x72\x20\x74\x68\x65\x20\x6c\x61\x7a\x79\x20\x64\x6f\x67"; |
Just as a reference, 4 bytes per char + 5.
Happy Challenging!
PS: Is there a site for javascript codegolf yet?
The geeks shall inherit the properties and methods of object earth.
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RE: my js ROUND3
1. Jul 2011 03:25:32 (12y 304d)
1. Jul 2011 03:25:32 (12y 304d)
And here is another "reference" with another length:
You probably might want to apply some rules to this one
Edit: Your javascript is priceless. But you cannot beat 185 chars with that math magic, can you? ;)
Edit2: How about this rule you need to have an array $x= new Array(116,104,101,32,...) in the final state, and you are not allowed to use functions
GeSHi`ed javascript Quelltext für 185
1 2 3 | $x=String.fromCharCode(116,104,101,32,113,117,105,99,107,32,98,114,111,119,110,32,102,111,120,32,106,117,109,112,115,32,111,118,101,114,32,116,104,101,32,108,97,122,121,32,100,111,103); |
You probably might want to apply some rules to this one
Edit: Your javascript is priceless. But you cannot beat 185 chars with that math magic, can you? ;)
Edit2: How about this rule you need to have an array $x= new Array(116,104,101,32,...) in the final state, and you are not allowed to use functions
The geeks shall inherit the properties and methods of object earth.
Zuletzt geändert von gizmore - 1. Jul 2011 03:32:31
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RE: my js ROUND3
1. Jul 2011 09:08:27 (12y 304d)
1. Jul 2011 09:08:27 (12y 304d)
sorry, rule1 says no more than 3 words in any encoded form which includes unicode and hex.
also base64/decimal/octal/binary/ascii etc etc ;)
there is no code golf sites for javascript yet that i know of, i've been searching for awhile
my math magic is going to get even more magic once i spend a bit more time on it to shorten them hehe.
Happy Coding.
also base64/decimal/octal/binary/ascii etc etc ;)
there is no code golf sites for javascript yet that i know of, i've been searching for awhile
my math magic is going to get even more magic once i spend a bit more time on it to shorten them hehe.
Happy Coding.
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RE: my js ROUND3
1. Jul 2011 19:56:35 (12y 304d)
1. Jul 2011 19:56:35 (12y 304d)
319 =)
nice calculations xen =)
EDIT: 275 =)
nice calculations xen =)
GeSHi`ed javascript Quelltext
1 | d=['the','over','quick'];e=[[[-14,7,19],[-16,7,2]],[[-3,-21,21,7]],[[-15,-3,6,20,3],[-7,0,4,13,8]]];function t(r,s){q='';for(p in d[r])q+=String.fromCharCode(d[r].charCodeAt(p)+e[r][s][p]);return q;};function z(x){document.write(x+' ')};z(d[0]);z(d[2]);z(t(2,0));z(t(0,0));z(t(2,1));z(d[1]);z(d[0]);z(t(1,0));z(t(0,1)); |
EDIT: 275 =)
GeSHi`ed javascript Quelltext
1 | d=['the','over','quick'];k=' ';e=[[[-14,7,19],[-16,7,2]],[[-3,-21,21,7]],[[-15,-3,6,20,3],[-7,0,4,13,8]]];function t(r,s){q='';for(p in d[r])q+=String.fromCharCode(d[r].charCodeAt(p)+e[r][s][p]);return q+k}alert(d[0]+k+d[2]+k+t(2,0)+t(0,0)+t(2,1)+d[1]+k+d[0]+k+t(1,0)+t(0,1)) |
Zuletzt geändert von livinskull - 2. Jul 2011 16:11:38
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RE: my js ROUND3
4. Jul 2011 02:10:38 (12y 301d)
4. Jul 2011 02:10:38 (12y 301d)
Hello. Nice game!
I got 175 chars with a run-of-the-mill Vigenere cipher.
However, as Gizmore said, the first rule should be explained better. What does 'encoding the words in any form' mean?
We need to represent the information in some way, so in the broadest sense, the task is impossible.
Is simple Cesar shift allowed? Would any method producing the result from another string be allowed?
I got 175 chars with a run-of-the-mill Vigenere cipher.
GeSHi`ed javascript Quelltext
1 2 3 | a='the quick brown ';b=' yvb zourc pmsn gms ijtk sgu';for(i=j=0;++i<28;j+=a[j]<'a')a+=(b[i]>' '?String.fromCharCode(((b[C='charCodeAt'](i)-a[C](j++)+26)%26)+97):' ');alert(a); |
However, as Gizmore said, the first rule should be explained better. What does 'encoding the words in any form' mean?
We need to represent the information in some way, so in the broadest sense, the task is impossible.
Is simple Cesar shift allowed? Would any method producing the result from another string be allowed?
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RE: my js ROUND3
4. Jul 2011 09:08:32 (12y 301d)
4. Jul 2011 09:08:32 (12y 301d)
the challenges output cannot be stored letter for letter in your code(43 in total)
instead you must make them, see my first code as example.
instead you must make them, see my first code as example.
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RE: my js ROUND3
14. Jan 2013 23:25:23 (11y 105d)
14. Jan 2013 23:25:23 (11y 105d)
there is indeed now javascript codegolf.- google: golf.js
its a challenge site so maybe they should be made aware of wechall?
its a challenge site so maybe they should be made aware of wechall?
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